#1
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àŢ¡¡ÓÅѧ
$3^x=4^y=5^z=60^k$áÅéÇ$\frac{1}{y} +\frac{1}{x}+\frac{1}{z} $ ÁÕ¤èÒà·èÒäÃ
(math contest Benchama 2008)
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#2
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ä´é $\frac{1}{k}$ ¤ÃѺ
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*1434* 4EvER =>...1434......àÅ¢¹ÕéÊÇ¡ÇèÒáÎÐ^^ |
#3
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$3=60^\frac{k}{x}$
$4=60^\frac{k}{y}$ $5=60^\frac{k}{z}$ $3x4x5=60^{k(\frac{1}{x}+\frac{1}{y}+\frac{1}{z})}$ $60^1=60^{k(\frac{1}{x}+\frac{1}{y}+\frac{1}{z})}$ $1=k(\frac{1}{x}+\frac{1}{y}+\frac{1}{z})$ $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=\frac{1}{k}$ |
#4
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¢Íº¤Ø³·Ø¡¤¹ÁÒ¡¹Ð¤ÃѺ ^_^
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#5
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ÊͺÁÐÃ×¹¹ÕéáÅéÇ à¤Ã×èͧàÂç¹à¨ÕêºàŤÃѺ
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#6
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¢ÍãËé⪤´Õ¹Ð¤ÃѺ (¾Õè¼Á¡çàªè¹¡Ñ¹¤ÃѺ)
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