#1
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โจทย์พหุนาม
1. ถ้า $\frac{x^5y-8x^2y^4}{x^4y+4x^2y^3+16y^5} \times \frac{x^2-2xy+4y^2}{x^2-4y^2} = \frac{P(x)}{x+2y} $ แล้ว $P(x)$ คือพหุนามใด
2. ถ้า $\frac{(3x-12y)^{-\frac{1}{2}}(4x+y)^{\frac{1}{2}}}{(12x^2-45xy-12y^2)^{-\frac{3}{2}}} = 486$ และ $(x^2+1)(4x+y-9)=0$ แล้ว $x-4y$ มีค่าเท่าใด
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#2
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1. $P(x)=x^2$
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#3
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ช่วยแนะนำวิธีคิดหน่อยครับ
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Numbers rule the Universe. |
#4
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ดึง $x^2y$ แล้วจะเจอพจน์ผลต่างกำลังสาม
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Hope is what makes us strong. It's why we are here. It is what we fight with when all else is lost. |
#5
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2.Hint $4x+y=9$ และ ลองให้ $x-4y=A$
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Hope is what makes us strong. It's why we are here. It is what we fight with when all else is lost. |
#6
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ขอบคุณครับ
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Numbers rule the Universe. |
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