#1
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ÊÍǹ
$f(x) = x\bigwedge 5/(5x\bigwedge 4-10x\bigwedge 3+10x\bigwedge 2-5x+1)
¶éÒ x_i=i/2009 àÁ×èÍ i = 1-2009 ¨§ËÒ \Sigma f(x_i) $ 26 ¾ÄȨԡÒ¹ 2011 20:46 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ »Ò¡¡Òà«Õ¹ |
#2
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ã¤Ã¡çä´éªèÇÂá»Å˹èÍÂ
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#3
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¶éҨѺ㨤ÇÒÁäÁè¼Ô´ »Ò¡¡Òà«Õ¹¨ÐºÍ¡ÇèÒàÍÒ⨷ÂìàâҤ³ÔµÁÒ¨Ò¡ (ÊѺʹÍÅǹ) ¤ÃѺ
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#4
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ÍéÒ§ÍÔ§:
¢é͹Õé¡çÊѧࡵÇèÒ $$f(x)=\frac{x^5}{x^5-(x-1)^5}=\frac{x^5}{x^5+(1-x)^5}$$ ¨Ö§ä´éÇèÒ $f(x)+f(1-x)=1$ µèͨҡ¹Õé¡çäÁèÂÒ¡áÅéÇ Åͧ¨Ñº¤Ùè´Ù (ÍÂèÒÅ×Á $f(x_{2009})=1$) ÇèÒáµè·ÓäÁèÁÒâ¼Åè㹺ÍÃì´àâҤ³ÔµÅèÐà¹ÕèÂ
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keep your way.
13 ¡Ñ¹ÂÒ¹ 2011 22:39 : ¢éͤÇÒÁ¹Õé¶Ù¡á¡éä¢áÅéÇ 1 ¤ÃÑé§, ¤ÃÑé§ÅèÒÊØ´â´Â¤Ø³ PP_nine |
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